OneofOne
Silver Baronet of the Realm
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Quick, call Merlin, he's got this shit!Can we have fun with Order of Operations?
(8+4/22)-5*3?3=?
Quick, call Merlin, he's got this shit!Can we have fun with Order of Operations?
(8+4/22)-5*3?3=?
Can we have fun with Order of Operations?
(8+4/22)-5*3?3=?
You got the right answer, but it should have been 9 - (5*3/3) = 9-(5*1) instead of 9-5(1). The question is....is there a difference and will it always work either way?
(8+(4/(2^2
+(-5
*3)/3)
So if I read the video right the unambiguously right answer would always be
2 ^ 2 = 4
4 / 4 = 1
8 + 1 = 9
9 + (-5) = 4
4 * 3 = 12
12 / 3 = 4
Ok, now I was probably taught wrong. with pedmas the d/m and a/s are interchangable. So to separate terms, at first glance, that would beYou got the right answer, but it should have been 9 - (5*3/3) = 9-(5*1) instead of 9-5(1). The question is....is there a difference and will it always work either way?
The answer is no.
So try this....10-6*8?2=?
Yo, you right monic. Sheeeeeeiiiiiiit!Ok, now I was probably taught wrong. with pedmas the d/m and a/s are interchangable. So to separate terms, at first glance, that would be
(-6*8)/2 + 10 = 10-6*8?2
-6 * 8 =
-48 / 2 =
-24 + 10=
-14 = 10-6*8?2
Edit: Fixed. I forgot to distribute.You got the right answer, but it should have been 9 - (5*3/3) = 9-(5*1) instead of 9-5(1). The question is....is there a difference and will it always work either way?
The answer is no.
So try this....10-6*8?2=?
I don't think so. In the above example 10-6*8?2=? if you do it your way: (10-6)*(8/2)=16. But if you do it by order of operations, you get 10-[(6*8)/2]=-14 or 10-[6(8/2]=-14. So in a way you're right you can pair them either way but only when interchanging addition and subtraction or multiplication and division, but you can't switch A or S with M or D.Well see 1:40 in the video. As long as you only do any pair of numbers at a time it doesn't matter what order you do them in. That's the point I think.
My answer was was wrong because I didn't listen to the very video I linked. You can do it in any order so long as you remember some basics like multiplication distributes. (10-6)*(8/2) should beI don't think so. In the above example 10-6*8?2=? if you do it your way: (10-6)*(8/2)=16. But if you do it by order of operations, you get 10-[(6*8)/2]=-14 or 10-[6(8/2]=-14. So in a way you're right you can pair them either way but only when interchanging addition and subtraction or multiplication and division, but you can't switch A or S with M or D.
You wouldn't distribute the 10 unless it was set up like (10-6)(8-2) and then you would use the FOIL method First, Outer, Inner, Last. (10*8) + (10*-2) + (-6*8) + (-6*2)My answer was was wrong because I didn't listen to the very video I linked. You can do it in any order so long as you remember some basics like multiplication distributes. (10-6)*(8/2) should be10*(8/2
+ (-6 *(8/2
and THEN it doesn't matter what order you do it it.
Distributing is some commy/socialist shit anyways. Freedom says you didn't forget anything important.Edit: Fixed. I forgot to distribute.