If you are thinking of bees, #2 would be royal jelly. Is there a name for the starting line of a chessboard?
Let's become british spies AKA logic puzzles challenge
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Szlia
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Chess or checkers were my first lead for 2) but the pawns are never called workers (and checkers was a translation issue because the terms are different in french and english).
I guess we know it is a 7x7 board now since we have the answers for step 3 (but not how to find them).
Hoss
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Shit, I thought I was hot on the trail to the last answer, then I saw Ahh Run already had it figured out. Layered.
It would be really funny if they put a blind alley in to fuck with people who got that question wrong.
Anyway, here's the next one.
Director GCHQ's Christmas Puzzle - Part 4
Congratulations on solving Part 3 of the Director's puzzle.
Part 4 consists of three questions, the answers to which can be combined to make an IP address.
Find the missing number in the following sequences:
2, 4, 8, 1, 3, 6, 18, 26, ?, 12, 24, 49, 89, 134, 378, 656, 117, 224, 548, 1456, 2912, 4934, 8868, 1771, 3543, ...
-101250000, -1728000, -4900, 360, 675, 200, ?, ...
321, 444, 675, 680, 370, 268, 949, 206, 851, ?, ...
Part 5 can be accessed via IP address A.B.C. Please check your answers below first.
It would be really funny if they put a blind alley in to fuck with people who got that question wrong.
Anyway, here's the next one.
Director GCHQ's Christmas Puzzle - Part 4
Congratulations on solving Part 3 of the Director's puzzle.
Part 4 consists of three questions, the answers to which can be combined to make an IP address.
Find the missing number in the following sequences:
2, 4, 8, 1, 3, 6, 18, 26, ?, 12, 24, 49, 89, 134, 378, 656, 117, 224, 548, 1456, 2912, 4934, 8868, 1771, 3543, ...
-101250000, -1728000, -4900, 360, 675, 200, ?, ...
321, 444, 675, 680, 370, 268, 949, 206, 851, ?, ...
Part 5 can be accessed via IP address A.B.C. Please check your answers below first.
Hoss
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I need someone smarter than me to explain how you can get an IP address out of 3 numbers. It says it will be simply a.b.c, so it's not a case of some numbers being too long and you have to figure out where to split them. I thought about the possibility that one answer is a decimal, but that doesn't seem likely looking at the questions.
Oh and this will probably be a stupid question, but do brits have their commas and decimal points swapped on everything, or is it just in certain cases?
Oh and this will probably be a stupid question, but do brits have their commas and decimal points swapped on everything, or is it just in certain cases?
I don't know how they got it but I am guessing it was only three numbers because IP's can only be a digit between 0-255.
So the three numbers look like they were 5230, 87, and 208.
You can't have an IP as 523 or as 230 so you have to split it as 52.30.
So the three numbers look like they were 5230, 87, and 208.
You can't have an IP as 523 or as 230 so you have to split it as 52.30.
Hoss
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Sure, but the directions specifically say it will be A.B.C. Even if you look at the code in the page source
if ((res[0] == 1824745082) && (res[1] == 560037081)) {
$("#answercheckresult").html("All your answers are correct!<br/><br/>Please go to page <b>next.html</b> at IP address <b>"+$("#answer_a").val()+"."+$("#answer_b").val()+"."+ $("#answer_c").val()+"</b> for Part 5.");
if ((res[0] == 1824745082) && (res[1] == 560037081)) {
$("#answercheckresult").html("All your answers are correct!<br/><br/>Please go to page <b>next.html</b> at IP address <b>"+$("#answer_a").val()+"."+$("#answer_b").val()+"."+ $("#answer_c").val()+"</b> for Part 5.");
Yeah I don't know and I am not involved in it at all just saying how I think they came up with it. Unless one of the numbers turned out to be a decimal number maybe.
Szlia
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So I solved Message:
It's a sudoku with letters and the additional clue is that the yellow diagonal spells MERRYXMAS. The answer is supposed to be "Extract answer from completed grid by reading the top row from left to right." so: MXAHRYESP. Not the sexiest of answer, but if it was not a random string of letters, you would just bypass the problem with an anagram solver.
It's a sudoku with letters and the additional clue is that the yellow diagonal spells MERRYXMAS. The answer is supposed to be "Extract answer from completed grid by reading the top row from left to right." so: MXAHRYESP. Not the sexiest of answer, but if it was not a random string of letters, you would just bypass the problem with an anagram solver.
It looks like a backwards ampersand to me but I will trust you on duck since I am not even working on this at all
Szlia
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Well... it looks more like a duck on my piece of paper!
I had a break through with Algebraic that was followed immediately by a cold shower: the realization that solving the thing will be super long and with a ton of chess logic and since I am not very good at chess it sounds like it will be super easy to make mistakes (you have to deduce what pieces can be or cannot be based only on location and color).
I had a break through with Algebraic that was followed immediately by a cold shower: the realization that solving the thing will be super long and with a ton of chess logic and since I am not very good at chess it sounds like it will be super easy to make mistakes (you have to deduce what pieces can be or cannot be based only on location and color).
Szlia
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By the magic of taking a dump with a notepad, I solved the first sequence of stage 4:
2, 4, 8, 1, 3, 6, 18, 26, ?, 12, 24, 49, 89, 134, 378, 656, 117, 224, 548, 1456, 2912, 4934, 8868, 1771, 3543, ...
It's the powers of 2 written by skipping every other number. so 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024, etc....
2, 4, 8, 1, 3, 6, 18, 26, ?, 12, 24, 49, 89, 134, 378, 656, 117, 224, 548, 1456, 2912, 4934, 8868, 1771, 3543, ...
It's the powers of 2 written by skipping every other number. so 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024, etc....
Szlia
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I solved the 3rd sequence of step 4!
321, 444, 675, 680, 370, 268, 949, 206, 851, ?, ...
You have to consider each digit independently, like a 0 to 9 wheel. and from the first three digits you kind of weave a +1 thread a +2 thread and a +3 thread. What I mean is that each thread goes 1st slot to 2nd slot to 3rd slot to 1st slot etc. So:
The +1 thread goes: 3.. -> .4. -> ..5 -> 6.. -> .7. -> etc
The +2 thread goes: .2. -> ..4 -> 6.. -> .8. -> ..0 -> etc
The +3 thread goes ..1 -> 4.. -> .7. -> ..0 -> 3.. -> etc
So the answer is 208.
There probably be is a more simple way to explain it, but heh.
321, 444, 675, 680, 370, 268, 949, 206, 851, ?, ...
You have to consider each digit independently, like a 0 to 9 wheel. and from the first three digits you kind of weave a +1 thread a +2 thread and a +3 thread. What I mean is that each thread goes 1st slot to 2nd slot to 3rd slot to 1st slot etc. So:
The +1 thread goes: 3.. -> .4. -> ..5 -> 6.. -> .7. -> etc
The +2 thread goes: .2. -> ..4 -> 6.. -> .8. -> ..0 -> etc
The +3 thread goes ..1 -> 4.. -> .7. -> ..0 -> 3.. -> etc
So the answer is 208.
There probably be is a more simple way to explain it, but heh.